diketahui persamaan termokimia N2(g) + 3H2(g) ----> 2NH3(g) ΔH°f = - 92,22 kJ berapakah entalpi pembentukan standar (ΔH°f) dari NH3(g)?

N2(g) + 3 H2(g) => 2 NH3(g) ΔH = -92,22 kJ

ΔH°f NH3(g) ... ?

2 mol NH3 = -92,22 kJ
1 mol = x

2/1 = -92,22/x
2 = -92,22/x
2x = -92,22
x = -92,22/2
x = -46,11 kJ/mol

ΔH°f NH3 = -46,11 kJ/mol