tentukan (fog)(2) dan (gof) untuk fungsi f(x)=4x+1dan g(x)=3x-5

1.fog = f(g(x))
=f(3x-5)
=4(3x-5)+1
=12x-20+1
=12x-19
fog(2)=12(2)-19
=5
2.gof = g(f(x))
=g(4x+1)
=3(4x+1)-5
=12x+3-5
=12x-2

f(x) = 4x + 1
g(x) = 3x - 5

(f • g)(x) = 4(3x - 5) + 1
(f • g)(x) = 12x - 20 + 1
(f • g)(x) = 12x - 19
(f • g)(2) = 12(2) - 19
(f • g)(2) = 24 - 19
(f • g)(2) = 5

(g • f)(x) = 3(4x + 1) - 5
(g • f)(x) = 12x + 3 - 5
(g • f)(x) = 12x - 2