Tolong no. 10, 22 dan 26 pake cara

10. jika f(x) = (ax + b)/(cx + d) --> f⁻¹(x) = (dx - b)/(-cx + a)

f(x)= (3-2x) /(3x-4)  --> f(x) = (-2x + 3)/(3x - 4)
f⁻¹(x)  = (-4x - 3)/ (-3x - 2) atau  f⁻¹(x) = (4x+3)/(3x+2)

22.  f(x) = { g(x))ⁿ --> f ' (x ) = n . g(x)ⁿ⁻¹.  g'(x)
f(x)= (3 - 2x³)⁴
f ' (x) = 4 (3-2x³)³ (-6x²)
f ' (x) = -24x² (3 -2x³)⁴

26. ₋₁³∫6x² - 4x + 1 dx =

= 2x³ - 2x² + x ]³₋₁
= 2(28) - 2(8) + (4)
= 56 - 16 + 4
= 44