Jawabannya jadinya brp yaa kak?

integral parsial
∫ x (3x - 5)⁵ dx

def ...... int
x............(3x-5)⁵
1.........1/3. 1/6. (3x-5)⁶
0.........1/3. 1/6. 1/3.1/7 (3x-5)⁷
.
= 1/18 x (3x-5)⁶ - 1/18. 1/21 (3x-5)⁷
= 1/126 (x-5)⁶ [ 7x - 3 (3x-5)]
= 1/126 (x-5)⁶ [ 7x -9x + 15 ]
= 1/126 (x-5)⁶ [15 - 2x]