di ketahui f(2x-1) = 4x²+2x-5 maka f(2)

langsung aja y

misal
f(2x-1) = a
f(x) = (a+1) / 2

soal menjadi
f(x) = 4(a+1 /2)² + 2(a+1/2) - 5
f(x) = 4(a²+2a+1 / 4) + a+1 - 5
f(x) = a² + 2a + 1 + a + 1 - 5
f(x) = a² + 3a - 3
f(x) = x² + 3x - 3

maka
f(2) = 2² + 3(2) - 3
f(2) = 4 + 6 - 3
f(2) = 7

semoga berguna +_+