berapakah massa (NH4)2 SO4 yang diperlakukan untuk membuat 1000 ml laruran (NH4)2SO4 dengan ph 5 ? (diketahui Mr (NH4)2SO4=132,kb NH3=10-5

Materi Hidrolisis Garam
Kimia Kelas 11

pH = -log[H+]
5 = -log[H+]
[H+] = 10^-5

[H+] = akar(Kw/Kb x M garam)
10^-5 = akar(10^-14/10^-5 x M garam
(10^-5)^2 = 10^-9 x M
M garam = 10^-1

(NH4)2SO4 --> 2NH4+ + SO4 2-

mol NH4 = M x V = 10^-1 x 1 = 10^-1
mol (NH4)2SO4 = 1/2 x mol NH4 = 1/2 x 10^-1 = 5 x 10^-2

massa (NH4)2SO4 = Mr x mol N42SO4
massa (NH4)2SO4 = 132 x 5 x 10^-2 = 6,6 gr