hitunglah NH4OH 0.005 m kb=1,8×10^-5
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Pertanyaan
hitunglah NH4OH 0.005 m kb=1,8×10^-5
1 Jawaban
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1. Jawaban nadinepr
[OH-]=√Kb×M
=√1,8×10^-5 × 0,005
=√9×10^-8
=3×10^-4
pOH=-log3×10^-4
=4-log3
pH=14-(4-log3)
=10+log3