adik membeli 2 kg mangga 1 kg duku dan 2 kg anggur seharga Rp 40.000. kakak membeli 2 kg mangga 2 kg duku dan 3 kg anggur seharga Rp 60.000. paman membeli 4 kg

mangga= x
duku =y
anggur =z
(1) 2x+y+2z =40000
(2) 2x+2y+3z =60000
(3)4y+z+4x= 70000
2x+y+2z??
eliminasi (1) dan (2)
2x+y+2z= 40000|x2| 4x+2y+4z=80000
2x+2y+3z=60000|x1| 2x+2y+3z=60000
2x + z = 20000(4)
eliminasi (1) dan (3)
2x+y+2z= 40000|x4| 8x+4y+8z=160000
4x+4y+z= 70000|x1| 4x+4y+z = 70000
4x + 7z = 90000(5)

eliminasi (4) dan (5)
2x+z = 20000|x7| 14x+7z= 140000
4x+7z= 90000|x1| 4x+7z= 90000
10x. = 50000
x= 5000
2(5000) +z= 20000
10000+z =20000
z=20000-10000
z=10000
2x+y+2z=40000
2(5000)+y+2(10000)=40000
10000+y+20000=40000
y= 40000-30000
y= 10000

2x+y+2z =
2(5000)+10000+2(10000)
10000+10000+20000= 40000 (uang yg dikeluarkan ayah)