Limit sin 2x/3-'akar'2x+9 . x mendekati 0

pnulisan mtk yg aneh....jika gini....
lim x→0 sin(2x)/(3 - √(2x + 9))
dikali sekawan
= lim x→0 (3 + √(2x + 9))sin(2x) / (9 - (2x+ 9))
= lim x→0 (3 + √(2x + 9))sin(2x)/(-2x)
= lim x→0 (3 + √(2x + 9))(-1)
= -(3 + √(0 + 9))
= -6