F(x)= 2x-13 g^-1(x) = x+4/5 h^-1=5x+7 nilai (fo(goj))^-1(3)...

fungsi invers

f(x) = 2x - 13 --> f⁻¹(x) =(x +13)/2
g⁻¹(x) = (x+4)/5
h⁻¹ (x) = 5x + 7

{f o(goh)}⁻¹ (3) = h⁻¹og⁻¹of⁻¹(3)
.
h⁻¹ og⁻¹ o f⁻¹(3) = h⁻¹ [ g⁻¹{ f⁻¹(3)}]
= h⁻¹ { g⁻¹ {(3+13)/2}
= h⁻¹ { g⁻¹(8)}
= h⁻¹ { (8+4)/5}
=h⁻¹ (12/5)
= 5 (12/5) + 7
= 12 + 7
= 19
h⁻¹ o g⁻¹ o f⁻¹ (3)= 19

{ fo(goh)}⁻¹(3) = ( h⁻¹ o g⁻¹ of⁻¹)(3) = 19