Jumblah tak hingga deret geometri 6+2akar3 +2+2/3akar3+...adalah

a = 6
r = 2√3 / 6 = √3/3

Sn = a/(1-r)
= 6/(1-√3/3)
= 6/((3-√3)/3)
= 6 x 3 /( 3-√3)
= 18 / (3-√3)
= 18(3+√3) / 9-3
= 18(3+√3) / 6
= 3(3+√3)
= 9+3√3