Matematika

Pertanyaan

2log16 + 4log8- 8log 4 + 16log8 =

2 Jawaban

  • ²log16 + ⁴log8 - ^8log4 + ^16log8

    ²log2⁴ + ²^²log2³ - ²^³log2² + ²^⁴log2³

    4(²log2) + (3/2)²log2 - (2/3)²log2 + (3/4)²log2

    4(1) + (3/2)(1) - (2/3)(1) + (3/4)(1)

    4 + 3/2 - 2/3 + 3/4

    48 + 18- 8+9 / 12
    67 / 12
  • ²log16 + ⁴log8 - 8log 4 + 16log8
    = 4 + 3/2 - 1/3/2 + 16log8
    = 4+ 1,5 - 2/3 + 16log 2³
    = 5,5 - 2/3 + 3. 16log2
    = 5,5 - 2/3 + 3. 1/²log16
    = 5,5 - 2/3 + 3.1/4
    = 5,5 - 2/3 + 3/4
    = 5,5 + 1/12
    = 5,5 + 0,083•••
    = 5,583••• atau 67/12

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