Tolong sertakan caranya yaa ;)
Matematika
aprsukma
Pertanyaan
Tolong sertakan caranya yaa ;)
2 Jawaban
-
1. Jawaban samuelruben110
3 - x - 1 / 2 < x - x - 3 / 4
6 / 2 - x - 1 / 2 < 4x / 4 - x -3 / 4
x + 7 / 2 < 3x - 3 / 4
4(x + 7) < 2(3x -3)
4x + 28 < 6x - 6
4x - 6x < -6-28
-2x < -34
x = 17 -
2. Jawaban arsetpopeye
3 - (x - 1)/2 < x - (x - 3)/4 ................. kedua ruas kali 4
12 - 2(x - 1) < 4x - (x - 3)
12 - 2x + 2 < 4x - x + 3
-2x + 14 < 3x + 3
-5x < -11
5x > 11
x > 11/5
x > 2,2