Matematika

Pertanyaan

Tolong sertakan caranya yaa ;)
Tolong sertakan caranya yaa ;)

2 Jawaban

  • 3 - x - 1 / 2 < x - x - 3 / 4
    6 / 2 - x - 1 / 2 < 4x / 4 - x -3 / 4
    x + 7 / 2 < 3x - 3 / 4
    4(x + 7) < 2(3x -3)
    4x + 28 < 6x - 6
    4x - 6x < -6-28
    -2x < -34
    x = 17
  • 3 - (x - 1)/2 < x - (x - 3)/4 ................. kedua ruas kali 4
    12 - 2(x - 1) < 4x - (x - 3)
    12 - 2x + 2 < 4x - x + 3
    -2x + 14 < 3x + 3
    -5x < -11
    5x > 11
    x > 11/5
    x > 2,2