Jika 3 log 4 = a maka 27 log 2 =......

³log4 = a ⇔ log4/log3 ⇔ log2² / log3 = 2log2/log3
^27log2 = log2/(log3³) = log2/3log3
supaya:
 2log2/log3 menjadi log2/3log3 maka:
kalikan 2log2/log3  dengan (1/6) sehingga:
(1/6)(2log2/log3) = log2/3log3 

karena  2log2/log3 = a maka:
log2/3log3  = (1/6)a atau a/6

semoga membantu

nb: sifat logaritma
1. ^alogb = logb/loga
2. log a^b = b.loga = bloga

3log4 = a => 3log2^2 = a => 2 . 3log2 = a => 3log2 = a/2
27log2 = 3^3log2 = 1/3 . 3log2 = 1/3 . a/2 = a/6 = 1/6 a