Bantu jawab ya :) sertakan cara, tolong

<acb/ab=<cab/bc
dikali silang jadi
sin 60 × bc = sin45 ×18
1/2 akar3 × bc = 1/2 akar2 ×18
bc=9 akar 2/ (1/2akar 3)
bc=9 akar 2 × 2 /akar 3
bc=18 akar2/akar 3 kalikan akar 3/ akar 3
bc= 18akar6/3
bc =6akar6

AB/(sin C) = BC/(sin A)
18/(sin 60°) = BC/(sin 45°)
18/(1/2 √3) = BC/(1/2 √2)
18/√3 = BC/√2
18√2/√3 = BC
BC = 18√2/√3 . √3/√3 = 18√6/3 = 6√6 cm