suatu suku banyak f(x) jika dibagi dengan x² + 2x - 3 bersisa 4x + 7 dan jika dibagi x² - x - 2 bersisa 3x - 1 . suku banyak f(x) tersebut jika dibagi x² + x -

langsung aja y

x² + x - 6 = (x+3)(x-2)

f(x) → x²+2x-3 = (x+3)(x-1)
f(-3) = 4(-3) + 7 = -12 + 7 = -5

f(x) → x²-x-2 = (x-2)(x+1)
f(2) = 3(2) - 1 = 6-1 = 5

maka

S = {f(2) - f(-3)x / 2-(-3)} + {2.f(-3) - (-3)f(2)/2-(-3)}

S = (5- (-5)x / 2+3) + (2.(-5) - (-3).(5) / 2+3

S = (5+5 x / 5) + (-10+15 / 5)

S = (10x / 5) + (5/5)

S = 2x + 1

jawabannya E

semoga berguna +_+