Jika di ketahui f(2x+1)=4x*2 +2x-5 hitulah f(2)

f(2x + 1) = 4x² + 2x - 5
f(2x + 1) = (2x + 1)² - (2x + 1) - 5
f(x) = x² - x - 5
f(2) = 2² - 2 - 5 = -3

f(2x + 1) = 4x^2 + 2x - 5

2x + 1 = 2 => 2x = 1 => x = 1/2
f(2x + 1) = 4x^2 + 2x - 5
f(2(1/2) + 1) = 4(1/2)^2 + 2(1/2) - 5
f(1 + 1) = 4(1/4) + 1 - 5
f(2) = 1 + 1 - 5 = -3