jika besar sudut P3 = (4x - 18)° dan besar sudut Q3 = (2x+24)°, besar sudut P2 =…… plis jawab, pake cara

∠P3 = ∠Q3
4x - 18 = 2x + 24
4x - 2x = 18 + 24
2x = 42
x = 42/2
x = 21

∠P2 = 180 - ∠P3
∠P2 = 180 - (4x - 18)
∠P2 = 180 - (4(21) - 18)
∠P2 = 180 - (84 - 18)
∠P2 = 180 - 66
∠P2 = 114° (D)