Matematika

Pertanyaan

Yg d bsa dibantuin ga?
Yg d bsa dibantuin ga?

1 Jawaban

  • Lim [1/(x^3 + 1)] [x/2 - 2/(x - 3)]
    = Lim (1/(x^3 + 1)) (x(x - 3) - 2(2))/2(x - 3)
    = Lim (1/(x^3 + 1)) (x^2 - 3x - 4)/2(x - 3)
    = Lim (x^2 - 3x - 4) / 2(x - 3)(x^3 + 1)
    = Lim (x - 4)(x + 1) / 2(x - 3)(x + 1)(x^2 - x + 1)
    = Lim (x - 4) / 2(x - 3)(x^2 - x + 1)
    = (-1 - 4) / 2(-1 - 3)((-1)^2 - (-1) + 1)
    = (-5) / 2(-4)(3)
    = 5/24