salah satu akar persamaan kuadrat mx2-3x+1=0 dua kali akar yang lain, maka nilai m adalah

mx^2 - 3x + 1 = 0

x1 = 2x2

x1 + x2 = 3/m
2x2 + x2 = 3/m
3x2 = 3/m
x2 = 1/m
x1 = 2 × 1/m = 2/m

x1 . x2 = 1/m
2/m . 1/m = 1/m
2/m^2 = 1/m
2/m = 1/1
m = 2

Jawaban: E

x1 = 2x2
x1 + x2 = -b/a
2x2 + x2 = -(-3)/m
3x2 = 3/m
m = 3 / 3x2 = 1/x2

x1.x2 = c/a
2x2.x2 = 1/m
2x2² = 1 / (1/x2)
2x2² = x2
x2²/x2 = 1/2
x2 = 1/2

m = 1 / x2 = 1 / (1/2) = 2