Tentukan Ph dari : 50 ml larutan CH3COOH 0,3 M dengan 50 ml Ca(OH)2 0,1 M. Ka CH3COOH = 1×10^-5

Mnrt aku gini, maaf kalau salah..

50 mL CH3COOH 0,3 M + 50 mL Ca(OH)2 0,1 M
Ka = 1 × 10^-5

pH ... ?

n CH3COOH = M × V
n CH3COOH = 0,3 × 50 mL
n CH3COOH = 15 mmol

n Ca(OH)2 = M × V
n Ca(OH)2 = 0,1 × 50 mL
n Ca(OH)2 = 5 mmol

#Reaksi
... 2 CH3COOH + Ca(OH)2 => Ca(CH3COO)2 + 2 H2O
M : ........ 15 .............. 5
R : ......... 10 ............. 5
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S : .......... 5 ............. --- ..................... 5 .................. 10

[H^+] = Ka × asam lemah/basa konjugasi
[H^+] = 10^-5 × 5/5
[H^+] = 10^-5

pH = - log [H^+]
pH = - log 10^-5
pH = 5