yang jago matematika minta bantuannya pleasee... diketahui f(x)= 2x-1/x+5, untuk x ≠ -5. jika f(a) = 0 , tentukan nilai f^-1(a)

f(a) = 0
2a-1/a+5 = 0
2a-1 = 0
2a = 1
a = 1/2

misal f(x) = y
2x-1/x+5 = y
xy+5y = 2x-1
xy-2x = -5y-1
x(y-2) = -5y-1
x = -5y-1/y-2
x = 5y+1/2-y
f^-1(x) = 5x+1/2-x

f^-1 (a) = 5(1/2)+1/2-1/2
= (5/2+1)/(4-1/2)
= (5+2/2)/(3/2)
= (7/2)/(3/2)
= 7/2 x 2/3
= 7/3