tolong jawab semua soal matematika ini harus pakai cara kalau enggak pakai cara enggak aku like ...

1. Rumus keliling lingkaran = [tex] \pi [/tex] × d
[tex] \frac{22}{7} [/tex] × 14 = 44 cm

3,14 × 16 = 50,24

(3,14 × 6) + (3,14 × 4) = 31,4 cm

2.
 
1. r = 12 cm
d = 12 × 2 = 24 cm
[tex] \pi [/tex] = 3,14
K = 3,14 × 24 = 75,36 cm

2. r = [tex] \frac{d}{2} [/tex] = [tex] \frac{63}{2} [/tex] = 31,5 cm
d = 63 cm
[tex] \pi [/tex] = 3,14
K = 3,14 × 63 = 197,82 cm

3. r = [tex] \frac{1}{2} [/tex] × [tex] \frac{314}{3,14} [/tex] = 50 cm
d = 2 × 50 = 100 cm
[tex] \pi [/tex] = 3,14
K = 314 cm

4. r = 35 cm
d = 70
[tex] \pi [/tex] = [tex] \frac{22}{7} [/tex]
K = [tex] \frac{22}{7} [/tex] × 70 = 220 cm