beserta pembahasannya!

semoga membantu .........

NH3 0,1 M mempunyai pH yang sama dengan NaOH 10^-3 M.

pH garam (NH4)2SO4 0,1 M ... ?

*[OH^-] NaOH
[OH^-] = b × Mb
[OH^-] = 1 × 10^-3
[OH^-] = 10^-3

*Kb NH3
[OH^-] NaOH = [OH^-] NH3
[OH^-] = √( Kb × Mb )
10^-3 = √( Kb × 0,1 )
(10^-3)^2 = (√( Kb × 0,1 ) )^2
10^-6 = Kb × 0,1
Kb = 10^-6/0,1
Kb = 10^-5

*pH garam (NH4)2SO4 0,1 M

(NH4)2SO4 => 2 NH4^{+} + SO4^2-
..... 0,1 M .............. 0,2 M ........ 0,1 M

[H^+] = √( Kw/Kb × M kation )
[H^+] = √( 10^-14/10^-5 × 0,2 )
[H^+] = √( 10^-9 × 0,2 )
[H^+] = √( 10^-10 × 2 )
[H^+] = 10^-5 × √2

pH = - log [H^+]
pH = - log 10^-5 × √2
pH = 5 - log √2