Bila Sin x + Cos x = 1/3 ,hitunglah: A.Sin x Cos x B.Sin³ x + Cos³ x C.Sin x - Cos x D.Cos/1-Sin x + Sin x/1-Cos x *Kasih Tauin Caranya Yahh

bila Sin x + Cos x = 1/3 ,hitunglah:
A.Sin x Cos x
Sinx + cosx = 1/3 (kedua ruas kuadratkan) (sin x + cosx)²=(1/3)²
sin²x + 2sinxcosx + cos²x = 1/9
2sinxcosx + 1 = 1/9
2sinxcosx = 1/9 - 1
2sinxcosx= -8/9
sinxcosx = -8/9 x 1/2
sinxcosx = -4/9

B.Sin³ x + Cos³ x
(sinx + cosx)(sin²x - sinxcosx+cos²x)
(1/3)(1-2(-4/9))
(1/3)(1+8/9)
(1/3)(17/9)
17/27

C.Sin x - Cos x
Misal nilai
sinx - cosx = p²
(sinx - cosx)²=p²
sin²x-2sinxcosx+cos²x =p²
1-2(-4/9)=p²
1+(8/9)=p²
p² = 17/9
p = √(17/9)
p=⅓√17

D.Cos/1-Sin x + Sin x/1-Cos x
(cosx)(1-cosx) + sinx(1-sinx) /(1-sinx)(1-cosx)
cosx-cos²x + sinx-sin²x / 1-cosx-sinx+sincosx

cosx + sinx - (cos²x + sin²x) / 1-(cosx+sinx) + sinxcosx

1/3 - 1 / 1-(1/3)-4/9
-2/3 / (9-3-4 / 9)
-2/3 / (2/9)
-2/3 x 9/2
-3