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Pertanyaan

diketahui Ksp Mg(OH)2 = 4*10^-12 maka pH larutan jenuh Mg(OH)2 adalah

1 Jawaban

  • ksp = [Mg]2[OH-]
    4x10^-12 = (2s)2(s)
    4x10^-12 = 4s^3
    s^3= 4x10^-12/4
    s= akar^3 10^-12
    s = 10^-4
    [OH-] = s = 10^-4

    pOH = -log 10^-4 = 4-log10 = 4-1 = 3
    pH = 14-pOH = 14-4 = 10

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