Jika ^3 log 2 = m dan ^2 log 7 = n, maka ^14 log 54 sama dengan . . . . .

3log2 = m
2log7 = n
maka
3log7 = mn

14log54 =
3log54 / 3log14 =
3log(2 x 3³) / 3log(2 x 7) =
(3log2 + 3log3³) / (2log2 + 3log7) =
(m+3) / (1+mn)

pakai sifat logaritma alog b = clog b / clog a