diketahui rumus fungsi f(x)=ax+b jika f(-4)=13dan f(3)=-1 maka nilai f(-2)

f(x)=ax+b

f(-4)=13→a(-4)+b=13
-4a+b=13
b=4a+13

f(3)=-1→a(3)+b=-1
3a+4a+13=-1
7a=-1-13
7a=-14
a=-14÷7
=-2

b=4a+13
=4(-2)+13
=-8+13
=5

nilai f(-2)=-2(-2)+5
=4+5
=9

semoga membantu...
# maaf kalo salah...
tolong dijadikan yg tercerdas ya...