sin 30°+cos 330°+sin 150°/tan 45°+cos 210°=
Matematika
ALImaskur05
Pertanyaan
sin 30°+cos 330°+sin 150°/tan 45°+cos 210°=
2 Jawaban
-
1. Jawaban Azizahad
sin 30° + cos 330° + sin 150°/tan 45° + cos 210°
= 1/2 + 1/2√3 + 1/2/1 - 1/2√3
= 1 -
2. Jawaban EdyDarma
(sin30°+cos330°+sin150°)/(tan45°+cos210°)
= (sin30°+cos30°+sin30°)/(tan45°-cos30°)
= (½ + ½√3 + ½)/(1 - ½√3)
= (1 + ½√3)/(1 - ½√3)
= ((2+√3)/2)/(2-√3)/2)
= (2+√3)/(2-√3)
= 7 + 4√3