Sebanyak 50ml asam sulfat (H2SO4) 0,02 M dicampurkan dg 50ml NaOH 0,1 pH campuran yg terjadi adalah

50 mL H2SO4 0,02 M + 50 mL NaOH 0,1 M

pH campuran ... ?

n H2SO4 = M × V
n H2SO4 = 0,02 × 50 mL
n H2SO4 = 1 mmol

n NaOH = M × V
n NaOH = 0,1 × 50 mL
n NaOH = 5 mmol

#Reaksi
... H2SO4 + 2 NaOH => Na2SO4 + 2 H2O
M : ... 1 .............. 5
R : .... 1 .............. 2
_______________---
S : ... --- ............. 3 ............... 1 .............. 2

Yang sisa NaOH
M = n / V total
M = 3 / (50+50)
M = 3 / 100
M = 0,03

[OH^-] = b × Mb
[OH^-] = 1 × 0,03
[OH^-] = 0,03
[OH^-] = 3 × 10^-2

pOH = - log [OH^-]
pOH = - log 3 × 10^-2
pOH = 2 - log 3

pH = 14 - pOH
pH = 14 - (2 - log 3)
pH = 14 - 2 + log 3
pH = 12 + log 3