Matematika

Pertanyaan

lim x menuju 0 cos^2x.sinx-sin^3x/7x

1 Jawaban

  • jika gini 
    lim x→0 (cos²x sinx - sin³x)/(7x)
    = lim x→0 ((1 - sin²x)sinx(1 - sin²x))/(7x)
    = lim x→0 sinx(1 - sin²x)²/(7x)
    = lim x→0 sinx (cos²x)²/(7x)
    = lim x→0 (sinx / x)(cos^4(x) / 7)
    = (1)(cos^4(0) / 7)
    = 1/7

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