Harap bantuannya tentang integral soal tertera di gambar

u = sin x => du = cos x dx
Int (cos x sin^2 x) dx
= Int (sin x)^2 cos x dx
= Int u^2 du
= 1/3 u^3 | batas 0 sampai π/2
= 1/3 (sin x)^3 | batas 0 sampai π/2
= 1/3 (sin π/2)^3 - 1/3 (sin 0)^3
= 1/3 (1)^3 - 1/3 (0)^3
= 1/3